25m^2-20m=(5m-4)

Solution for 25m^2-20m=(5m-4) equation:

25m^2-20m=(5m-4)

We move all terms to the left:

25m^2-20m-((5m-4))=0


We calculate terms in parentheses: -((5m-4)), so:

(5m-4)

We get rid of parentheses

5m-4

Back to the equation:

-(5m-4)


We get rid of parentheses

25m^2-20m-5m+4=0

We add all the numbers together, and all the variables

25m^2-25m+4=0

a = 25; b = -25; c = +4;
Δ = b2-4ac
Δ = -252-4·25·4
Δ = 225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{225}=15$
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-25)-15}{2*25}=\frac{10}{50}
=1/5
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-25)+15}{2*25}=\frac{40}{50}
=4/5
$